Steph&Ryan's+Calorimetry+lab

=Calorimetry Lab=

Stephany and Ryan The purpose of this lab is to study the transfer of heat.


 * Lab Documents**: Include a link to any documentation provided for the lab or any references used in writing the lab report.

In this lab we took a calorimeter and measured its weight. Then we filled it with water and weighed it again. We subtracted the first weight with the second weight and that gave us the weight of the water. We then measured that temperature of the water by itself. Then we took at piece of metal at 100 degrees Celsius and put it in the calorimeter and watched the temperature. For the next part of the lab we did the same thing except we used a test tube of paraffin.

== added (Q)// || Heat added is equal to the mass multiplied by the specific heat of the object multiplied by the change in temperature. Q= m*c*(change in) t 187.1*4.186*46=3602.723(for the first part) 1754= 190.46*4.186*2.2(for the second part) Q= m*L+ m*c(liquid)*(change in)t+ m*c(solid)*(change in)t || temperature || The change in temperature is equal to the heat added divided by the mass multiplied by the specific heat of the object. change in temperature = Q/( m*c) This can also be found by subtracting the initial temperature by the final temperature. 100-26=74(this is for the first part) || heat || The specific heat is measured by dividing the heat added by the mass multiplied by the change in temperature. c=Q/(m*change in t) .43481=3602.723/(111.97*74) (this is for the first part) || heat || The latent heat is the heat added divided by the mass L=Q/m also you can use this formula to find Latent heat(this is the one we used) m*L+ m*c(liquid)*(change in)t+ m*c(solid)*(change in)t = Q (these are from the second part) 9.22*L+96.89+335.356=1754 9.22*L+432.246=1754 -1321.754=-9.22*L -1321.754/-9.22=(-9.22*L)/-9.22 143.357=L ||
 * //Heat
 * Change in
 * Specific
 * Latent
 * Results**: We found out the our metals specific heat was .43481J/g*(degrees)C. the metal that was closest to this was Iron. Iron's specific heat is .4494J/g*(degrees)C . To find this we used the formula for finding the specific heat, (shown above). The latent heat of fusion of paraffin is 143.357 J/g. We found this by using the formula for finding latent heat (also above).


 * Lab Questions**:
 * 1.In what ways did you attempt to make your results as accurate as possible? Describe how each way contributed to a more accurate result.**

One thing we did to make our results as accurate as possible, each measurement was taken carefully. That was very important to complete our calculations. Also when adding the metal we didn't waste any time. We treid to put the metal into our water fast so it did not get a chance to cool off. If it had cooled off a lot, or even a little, that would currupt our data.


 * 2. In what ways does the calorimeter fail as a closed system? What mathematical effects on your result would these failures have?**

During the paraffin part of the lab the calorimeter was not a closed system because the test tube was too big the cover could not go back. The mathematical effect was that the loss of heat altered the data.


 * Conclusion**: The calorimetry lab was a good experiment where we found a valid solution. We concluded that this experiment would be easy to reproduce the same results. The results would have been more accurate if the metal cyliders were not exposed to air. Or even if it was exposed for a less amount of time. Also when the test tube of paraffin was placed in the calorimeter we were not able to completely close the lid. Therefore the experiment was not closed; air was able to enter the chamber and effect the temperature.